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write the ions present in solution of na3po4 - AssociationVoting

📅 May 17, 2026 👤 scraface

May 17, 2026

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📌 \gcd(5^{24} - 1, 5^{36} - 1) = 5^{12} - 1.

📌 We now compute $ 5^{12} - 1 $:

📌 5^2 = 25, \quad 5^4 = (25)^2 = 625, \quad 5^8 = 625^2 = 390625,

📌 5^{12} = 5^8 \cdot 5^4 = 390625 \cdot 625.

📌 We compute $ 390625 \cdot 625 $:

📌 Break $ 625 = 600 + 25 $, so

📌 \cdot 600 = 390625 \cdot 6 \cdot 100 = (2,343,750) \cdot 100 = 234,375,000,

📌 \cdot 25 = (390625 \cdot 100)/4 = 39,062,500 / 4 = 9,765,625.

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