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📅 May 17, 2026 👤 scraface

May 17, 2026

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So $ b $ can be any value if $ a = 0 $, but not otherwise.
Alternatively, perhaps its: $ a(a + b) = 3a + ab $?
So $ a = 0 $. Then plug into equation:
So it holds for any $ b $ when $ a = 0 $.
But the problem asks for $ b $, implying a specific value.
Unless... perhaps its a system or theres more.
Alternatively, perhaps its a typo, and its:
$ a(a + b) = 3a + ab + c $, but not given.
Another possibility: the equation is meant to be solved for $ b $ when...
But looking at the format of previous problems, perhaps the intention...

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