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ight)^2 \cdot \left(rac13 - AssociationVoting

📅 May 16, 2026 👤 scraface

May 16, 2026

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Solution: To find the LCM, take the maximum exponent for each prime fa...
For $ 2 $: $ \max(4, 2) = 4 $
For $ 3 $: $ \max(1, 3) = 3 $
For $ 5 $: $ \max(0, 1) = 1 $
Thus, the LCM is $ 2^4 \cdot 3^3 \cdot 5 = 16 \cdot 27 \cdot 5 = 2160...
The least common multiple is $ \boxed{2160} $.
Question: What is the remainder when $ 12083 + 12085 + 12087 + 12089 $...
+ 12085 + 12087 + 12089 = (12083 + 12089) + (12085 + 12087) = 24172 +...
Now compute $ 48344 \mod 8 $. Since 1000 is divisible by 8, only the l...
\div 8 = 43 \text{ with remainder } 0

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Calculate:
10! = 3628800,\quad 3! = 6,\quad 5! = 120,\quad 2! = 2
\frac{3628800}{6 \cdot 120 \cdot 2} = \frac{3628800}{1440} = 2520
Thus, there are 2520 distinct activation sequences.
\boxed{2520}
Question: An AI startup trains a model using 6 identical blue data bat...
Solution: We compute the number of distinct permutations of a multiset...
\frac{13!}{6! \cdot 4! \cdot 3!}
Compute step-by-step:
13! = 6227020800,\quad 6! = 720,\quad 4! = 24,\quad 3! = 6

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